3x^2+22x=45

Solution for 3x^2+22x=45 equation:

3x^2+22x=45

We move all terms to the left:

3x^2+22x-(45)=0

a = 3; b = 22; c = -45;
Δ = b2-4ac
Δ = 222-4·3·(-45)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-32}{2*3}=\frac{-54}{6}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+32}{2*3}=\frac{10}{6}
=1+2/3
$